But I don't know what you mean with the `PeekA()` line. That's not safe of course because it's an invalid pointer, in this case you are trying to read a byte from address 5.
The english grammar is freeware, you can use it freely - But it's not Open Source, i.e. you can not change it or publish it in altered way.
Yes I mean exactly that part. My concern: the parameter inside the bracket can not turn to be an addition in any case. Am I right? Sorry if the question is dumb, but I don't know how it is decided if it's an increment or not.
Yes I mean exactly that part. My concern: the parameter inside the bracket can not turn to be an addition in any case. Am I right? Sorry if the question is dumb, but I don't know how it is decided if it's an increment or not.
If you write an expression like: a + b
the value of a itself is only increased by b, if a is in front of the code line.
So with "function(a+b)" you do not change the value of a itself.
With "c = a + b" you do not change the value of a itself.
Only with "a + b" alone, a is increased by b after its evaluation.