Geek Puzzle
- Joakim Christiansen
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It just doesn't sound right, if you can't know how much mass was drilled out how can you ever figure out what is remaining?akj wrote:@Derek
The problem can be solved (producing an answer in cubic metres) without knowing the width/diameter of the hole.
I like logic, hence I dislike humans but love computers.
@Joakim,
I know the sphere problem sounds impossible, but if you go carefully through the mathematics/geometry of it, you can reach a perfectly good solution without any tricks or cheating.
The answer is a number [greater than zero] of cubic metres.
Here are some formulae to help you:
The volume of a sphere is PI*r*r*r*4/3
The volume of a spherical cap is PI*h*h*(r-h/3)
The volume of a cylinder is PI*R*R*H
Where:
r is the radius of the sphere
h is the height of the spherical cap (measured perpendicularly from the centre of it's circular base)
R is the radius of the cylinder
H is the height of the cylinder
I know the sphere problem sounds impossible, but if you go carefully through the mathematics/geometry of it, you can reach a perfectly good solution without any tricks or cheating.
The answer is a number [greater than zero] of cubic metres.
Here are some formulae to help you:
The volume of a sphere is PI*r*r*r*4/3
The volume of a spherical cap is PI*h*h*(r-h/3)
The volume of a cylinder is PI*R*R*H
Where:
r is the radius of the sphere
h is the height of the spherical cap (measured perpendicularly from the centre of it's circular base)
R is the radius of the cylinder
H is the height of the cylinder
Anthony Jordan
- Rook Zimbabwe
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- Location: Cypress TX
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I think your question is flawedakj wrote:@Joakim,
Here are some formulae to help you:
The volume of a sphere is PI*r*r*r*4/3
The volume of a spherical cap is PI*h*h*(r-h/3)
The volume of a cylinder is PI*R*R*H
Where:
r is the radius of the sphere
h is the height of the spherical cap (measured perpendicularly from the centre of it's circular base)
R is the radius of the cylinder
H is the height of the cylinder
the best anyone can do with the information you gave is answer with a formula, not a number. There are too many variables...
oh and the German is the fish-lover
there is no sig, only zuul (and the following disclaimer)
WARNING: may be talking out of his hat
WARNING: may be talking out of his hat
- Rook Zimbabwe
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- Location: Cypress TX
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Wrong ^o^Rook Zimbabwe wrote:Please remember that over 80% of statistics are made up on the spot! 8)
That said... I am thinking that lisa has 20 pearls also... (did without involving any of that messy math stuff) so 3 more paerls than both would be .9%
The answer is, Mike has less pearls than Thomas and Lisa together.
Thomas = 20
Mike = 43
Lisa = 43 * 0,7 = 30,1 ~ 30
(20 + 30) > 43.
I knew I would make someone miscalculate even a simple puzzle like that ^_^
Hahaha you're busted Rook! ^o^
Is it just me or does anyone else read that as Lisa having 70% less than 43 = ~13, for Lisa to have 30 shouldn't it read Lisa has 70% of 43 ?Irene wrote:Thomas has 20 pearls, but his friend Mike has 43 pearls. Lisa has 70% less pearls than Mike. How many percent does Mike have more pearls than Thomas and Lisa together?