How to run a process from an other probgram.

[Holdlang]

How can i run a process from an other program? I have the memory adress where the process is starting, but when i try to CallFuntionFast($adress) it, i get an acces vioalation error.

i try this:

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Procedure VirtualProtectExMY(hwnd, adress, size.l)
  CallFunction (#PROCESS32LIB, "VirtualProtectEx", hwnd, adress, size.l, 128, @OrigMode)

EndProcedure

pHandle = OpenProcess_(#PROCESS_ALL_ACCESS, #False, pid)
ReadProcessMemory_(pHandle, $40107D,lives,1,0)
PrintN("lives:" + Hex(Asc(lives))) ;It works i get the firs byte of the process (push....)
VirtualProtectExMY(pHandle, $40107D, 24) ;I try to set read,write,exec access to the process in the other program
CallFunctionFast($40107D) ;and here is where it dies....

any idea pls?

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[El_Choni]

Maybe the other process function needs some parameters in the stack?

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CallFunctionFast($40107D, arg1, arg2...)

Also, make sure that you only need those 24 bytes (or a memory page) of the other process' memory.

BTW, how do you know the other process' function always resides at $40107D?

[Holdlang]

Maybe the other process function needs some parameters in the stack?

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CallFunctionFast($40107D, arg1, arg2...)

Also, make sure that you only need those 24 bytes (or a memory page) of the other process' memory.

It don't need. I call this process from test.exe, which already running:

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Procedure test()
   PrintN("Test ok!")
EndProccedure

The other program which is use the CallFunctionFast is named to fastcall.exe.

BTW, how do you know the other process' function always resides at $40107D?

Yes this is the problem. I searched the addres with tsearch but the problem is i think that it is in an other program(now in 1.exe), and fastcall can only call from the program which call it.
Like some process in the same source: CallFunctionFast(@test)

So i'm now wery upsett. Any idea how to access and run a process from an other program?

I need something like this:
FastCall(procid,_function_,[param1,param2,...])

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