I compiled a program with:
FontColor(*p\FontColor)
which works fine in Purbasic 6.10LTS
but gives syntax error in 6.11LTS
Fixed with:
i=*p\FontColor
FontColor(i)
So new compiler gives syntax error if the FontColor parameter is through a pointer
FontColor() bug Ubuntu 222.04 LTS
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ricardo59715
- New User

- Posts: 1
- Joined: Sun Jun 16, 2024 1:42 am
Re: FontColor() bug Ubuntu 222.04 LTS
Not enough code ...
What is FontColor?
What is FontColor?
My Projects ThreadToGUI / OOP-BaseClass / EventDesigner V3
PB v3.30 / v5.75 - OS Mac Mini OSX 10.xx - VM Window Pro / Linux Ubuntu
Downloads on my Webspace / OneDrive
PB v3.30 / v5.75 - OS Mac Mini OSX 10.xx - VM Window Pro / Linux Ubuntu
Downloads on my Webspace / OneDrive
