CallFunctionFast() question.

[jassing]

When using CallFunctionFast() - what does it do behind the scenes?

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Procedure who(ball.s="")
  Debug "has the "+ball
EndProcedure
*p=@who()
CallFunctionFast(*p)       ; not sending anything, so I expect the default parameter to to used ("").
CallFunctionFast(*p,@"") ; this works, but what if you don't know the default, or the default changes?	

the call is assembled to

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integer r0=PB_CallFunctionFast(p0);

I just assumed, no parameters, it would use the default specified in the parameter definition (ball.s="")

[idle]

use prototypes much better than call function fast

[jassing]

use prototypes much better than call function fast

ok, thanks.