About RegularExpression replace \1

[shu7734]

a.s="fsvFfs123fkasdjfk467566"
CreateRegularExpression(0,"(Ffs)(\d)")
ReplaceRegularExpression(0,a.s,"\1")

i want the result is

Ffs123

cann't suport \1\2 ？

example

Code: Select all

 
 If CreateRegularExpression(0, "(abC)(.+)")
    Result$ = ReplaceRegularExpression(0, "abC ABc zbA abc", "\1")
    Debug Result$ ; Will print "--- ABc --- abc"
  Else
    Debug RegularExpressionError()
  EndIf

i want debug output
abC