How can I find out, if the right or left mouse button was pressed on a panel
gadget?
Regards,
dige
PanelGadget and EventTypes()
Not so easy, but possible
Code: Select all
Case #WM_RBUTTONDOWN
;{-Right Button Down
If GetActiveWindow_()=MainWin And ignoreRightClick=#False
popup_File=-1
GetCursorPos_(mouse.POINT)
getwindowrect_(SciEdi,rect.RECT)
;{ PanelPopUp
count=CountGadgetItems(#gadget_main_PanelFile)-1
Id=GadgetID(#gadget_main_PanelFile)
getwindowrect_(Id,screen.RECT)
For i=0 To count
SendMessage_(Id,#TCM_GETITEMRECT ,i,rect.RECT)
rect\left+screen\left:rect\right +screen\left
rect\top +screen\top :rect\bottom+screen\top
If mouse\x>=rect\left And mouse\y>=rect\top And mouse\x<=rect\right And mouse\y<=rect\bottom
popup_File=i:i=count
ak=ListIndex(Sources())
SelectElement(Sources(),popup_File)
SetMenuItemState(#menu_PanelFile,#menu_File_Debugger,Sources()\debugger)
If Sources()\compileThis$
EnableMenuItem_(PanelFileMenu,#menu_File_Debugger,#MF_BYCOMMAND|#MF_GRAYED)
Else
EnableMenuItem_(PanelFileMenu,#menu_File_Debugger,#MF_BYCOMMAND|#MF_Enabled)
EndIf
SelectElement(Sources(),ak)
DisplayPopupMenu(#menu_PanelFile,MainWin)
EndIf
Next
;}
EndIf
Else
ignoreRightClick=#False
EndIf
;}
