byte and string question?

[BackupUser]

Restored from previous forum. Originally posted by cor.

I have the following values:

tmp.s="30"

message.l= $007f2890

How could I easily replace the value 28 in the 'message' with the value 30 from 'tmp' string

Using Windows 98 SE
Registered PB version : 3.2 (Windows)
--------------------------
C. de Visser
Author of Super Guitar Chord Finder
http://www.ready4music.com

[BackupUser]

Restored from previous forum. Originally posted by PB.

> tmp.s="30"
> message.l= $007f2890
>
> How could I easily replace the value 28 in the 'message' with the value 30
> from 'tmp' string

It depends on several things:

(1) Is message.l always going to be a six-character number (ie, the last six
characters "7f2890"), or will the first two zeros sometimes have numbers?

(2) Does the position of the digits to be swapped changed, or is it only the
two digits currently in the "28" position changing?

Anyway, this works for your specific example above:

Code: Select all

tmp.s="30"
message.l=$007f2890
a$="$00"+Hex(message) ; Create a 9-character string based on message.l
a$=Left(a$,5)+tmp+Right(a$,2) ; Replace positions 6 and 7 with tmp
Debug a$

PB - Registered PureBasic Coder

[BackupUser]

Restored from previous forum. Originally posted by cor.

Thanks Paul,

But how to get a$ into the original value message.l, that is my problem

Code: Select all

tmp.s="30"
message.l=$007f2890
a$="$00"+Hex(message) ; Create a 9-character string based on message.l
a$=Left(a$,5)+tmp+Right(a$,2) ; Replace positions 6 and 7 with tmp
Debug a$

PB - Registered PureBasic Coder

Using Windows 98 SE
Registered PB version : 3.2 (Windows)
--------------------------
C. de Visser
Author of Super Guitar Chord Finder
http://www.ready4music.com

[BackupUser]

Restored from previous forum. Originally posted by PB.

> But how to get a$ into the original value message.l, that is my problem

Do you mean like this?

Code: Select all

Procedure.l hex2dec(h$)
  ; h$ can be 0-FFFFFFF.
  h$=UCase(h$)
  For r=1 To Len(h$)
    d60
      d+Asc(a$)-55
    Else
      d+Asc(a$)-48
    EndIf
  Next
  ProcedureReturn d
EndProcedure
;
tmp.s="30"
message.l=$007f2890
Debug "Old = "+Str(message)
a$="$00"+Hex(message)
message=hex2dec(Left(a$,5)+tmp+Right(a$,2))
Debug "New = "+Str(message)

PB - Registered PureBasic Coder

[BackupUser]

Restored from previous forum. Originally posted by cor.

> But how to get a$ into the original value message.l, that is my problem

Do you mean like this?

Code: Select all

Procedure.l hex2dec(h$)
  ; h$ can be 0-FFFFFFF.
  h$=UCase(h$)
  For r=1 To Len(h$)
    d60
      d+Asc(a$)-55
    Else
      d+Asc(a$)-48
    EndIf
  Next
  ProcedureReturn d
EndProcedure
;
tmp.s="30"
message.l=$007f2890
Debug "Old = "+Str(message)
a$="$00"+Hex(message)
message=hex2dec(Left(a$,5)+tmp+Right(a$,2))
Debug "New = "+Str(message)

PB - Registered PureBasic Coder

Using Windows 98 SE
Registered PB version : 3.2 (Windows)
--------------------------
C. de Visser
Author of Super Guitar Chord Finder
http://www.ready4music.com

[BackupUser]

Restored from previous forum. Originally posted by cor.

Paul,

Thanks for your quick response, it works jippieeeeee

> But how to get a$ into the original value message.l, that is my problem

Do you mean like this?

Code: Select all

Procedure.l hex2dec(h$)
  ; h$ can be 0-FFFFFFF.
  h$=UCase(h$)
  For r=1 To Len(h$)
    d60
      d+Asc(a$)-55
    Else
      d+Asc(a$)-48
    EndIf
  Next
  ProcedureReturn d
EndProcedure
;
tmp.s="30"
message.l=$007f2890
Debug "Old = "+Str(message)
a$="$00"+Hex(message)
message=hex2dec(Left(a$,5)+tmp+Right(a$,2))
Debug "New = "+Str(message)

PB - Registered PureBasic Coder

Using Windows 98 SE
Registered PB version : 3.2 (Windows)
--------------------------
C. de Visser
Author of Super Guitar Chord Finder
http://www.ready4music.com