Stupido string questions..

[Killswitch]

Jesus, why are all of you producing such complicated solutions:

Code: Select all

String.s="aftershave"
Debug mid(String,findstring(String,"shave",1),len(String))

[PB]

Jesus, why are all of you producing such complicated solutions:

Code: Select all

String.s="aftershave"
Debug mid(String,findstring(String,"shave",1),len(String))

Because your solution doesn't cover both his scenarios.

[Trond]

Jesus, why are all of you producing such complicated solutions:

Code: Select all

String.s="aftershave"
Debug mid(String,findstring(String,"shave",1),len(String))

Why is that less complicated than this?

Code: Select all

String.s = "aftershave"
Debug PeekS(@String.s+Len("shave"))

[Joakim Christiansen]

[okasvi]

Jesus, why are all of you producing such complicated solutions:

Code: Select all

String.s="aftershave"
Debug mid(String,findstring(String,"shave",1),len(String))

Why is that less complicated than this?

Code: Select all

String.s = "aftershave"
Debug PeekS(@String.s+Len("shave"))

because of

PeekS()

Syntax

Text$ = PeekS(*MemoryBuffer [, Length])
Description

For advanced programmers only. Very useful to catch a string at the specified memory address. The string should be ended by a '0' character, else it will read the memory until a '0' is encounter. An optional length parameter (in bytes) can be specified.
Supported OS

All

[Trond]

Advanced but simple.

[josku_x]

Well, atleast you all get the same result