I compiled a program with:
FontColor(*p\FontColor)
which works fine in Purbasic 6.10LTS
but gives syntax error in 6.11LTS
Fixed with:
i=*p\FontColor
FontColor(i)
So new compiler gives syntax error if the FontColor parameter is through a pointer
Search found 1 match
- Sun Jun 16, 2024 1:48 am
- Forum: Coding Questions
- Topic: FontColor() bug Ubuntu 222.04 LTS
- Replies: 1
- Views: 470