PureBasic Forums - English

Solve Equation with unknowns :
How can i Solve for 227.95
from the above equation ,
that is , rearrange the above equation to calculate 227.95 ??

227.95 = ??

227.95 = (617.365264854623888 - 543.12314272 * 1.09628415) / (1.09628415 - 1)

Josh is right
Or to put it into a formula

Did here anybody quickly have to do his homework early in the morning?

x.d = ((543.12314272 + 227.95) * 1.09628415) - 617.365264854623888
Debug x

Josh wrote:Did here anybody quickly have to do his homework early in the morning?

+1


(I miss the "thumbs up" feature in this forum)

I don't think he wants that simple equation to be solved but rather wants it to be solved programmatically.

said wrote:x.d = ((543.12314272 + 227.95) * 1.09628415) - 617.365264854623888
Debug x

No good solution. The result is in the rhs-part too

NicTheQuick wrote:I don't think he wants that simple equation to be solved but rather wants it to be solved programmatically.

Thought this at beginning too. But to solve a formula programmatically, the question had to be much more general.

Josh wrote:

Code: Select all

617.365264854623888 = ((543.12314272 + 227.95) * 1.09628415) - 227.95

227.95 = (617.365264854623888 - 543.12314272 * 1.09628415) / (1.09628415 - 1)

i didn't think i'd get so many quick Replies
Thanks Josh , Wilbert , and said ..... very much appreciated !

its no real School Homework ,
i just wanted to reverse-engineer SuperFlow's Engine Dyno Friction Torque value

Josh i had this :
(617.365264854623888 - 543.12314272) / (1.09628415 - 1)

but just could not solve it and get to your correct solution here :
227.95 = (617.365264854623888 - 543.12314272 * 1.09628415) / (1.09628415 - 1)


reverse engineer Friction Torque from CBTQ , UBTQ , and SAE J607 STP Weather Correction Factor

Friction Torque Lbs-Feet = 227.95 from SuperFlow Linear Spline Lookup Table with 3.800 = Stroke @ 8100 RPM = 5130.0 FPM Piston Speed

Engine Size = 505.21836418 Cubic Inches Cylinders = 8 Bore = 4.60000 Stroke = 3.80000
Peak HP RPM = 8100 Corrected Brake TQ = 617.36569824 UnCorrected Brake TQ = 543.12314272
Peak HP RPM = 8100 Corrected Brake HP = 952.12387010 UnCorrected Brake HP = 837.62429637

SuperFlow SAE J607 (June1974) STP Weather Correction Factor = 1.09628415
SuperFlow SAE J607 (June1974) STP Weather + Friction Correction Factor = 1.13669562 @ 8100 RPM
SuperFlow Air Correction = 0.87050582
SuperFlow Air Density Lbs./CuFt = 0.06641959
Actual Air Density % PerCent = 89.61399223
Actual Air Density Lbs./CubicFoot= 0.0685316293 Actual Air Density KG/M3 = 1.0977714048

Everytime I see inches and other imperial units my eyes hurt.

NicTheQuick wrote:Everytime I see inches and other imperial units my eyes hurt.

i feel the same way .. but in opposite English Units direction

with just a Mouse click , it converts over to Metric Units

here's a ScreenShot of English Units inputs .. but with Metric Units also displayed :

NicTheQuick wrote:Everytime I see inches and other imperial units my eyes hurt.

I love it. Anglo-american units of length

I have a nice quote here:

"In the metric system, one milliliter of water fills a space of exactly one cubic centimeter, weighs one gram, and needs one calorie to heat it by one degree Celsius, which equals one percent of the difference between its freezing and boiling points.
A quantity of hydrogen of the same weight contains exactly one mole of atoms.

In the American system, however, one can not calculate these units directly. So, when asked, "How much energy does it take to bring a gallon of room-temperature water to a boil?" reasonable way only with "F *** you!" reply."

Author:
Unknown

Everything has its advantages and disadvantages.

But the systems should never be mixed.

ccode wrote:I have a nice quote here:

"In the metric system, one milliliter of water fills a space of exactly one cubic centimeter, weighs one gram, and needs one calorie to heat it by one degree Celsius, which equals one percent of the difference between its freezing and boiling points.
A quantity of hydrogen of the same weight contains exactly one mole of atoms.

In the American system, however, one can not calculate these units directly. So, when asked, "How much energy does it take to bring a gallon of room-temperature water to a boil?" reasonable way only with "F *** you!" reply."

Author:
Unknown

Everything has its advantages and disadvantages.

But the systems should never be mixed.

my Digital Thermostat went out on my old Central AC Unit
they replaced it with a new upgraded Digital Thermostat
that had options to use + display either Fahrenheit or Celsius or Centigrade degrees

the problem was it was controlling temperature thru about a 4 degree spread like +2 above the setting to -2 deg below the setting
the AC Guy said it looks like its controlling the temp with Centigrade degrees , even though its setup to use Fahrenheit degrees

so for about a year that upgraded Digital Thermostat was a hassle

sort of luckily , the AC Unit went out
i replaced it with new Lennox signature series 5 ton 2-stage AC Unit
with WiFi Digital Thermostat that controls temperature +- 1.0 deg Fahrenheit scale ... what a great AC Unit

super comfortable Day and Night with it constantly maintaining within +- 1.0 DegF temps
... best was it cut my Electric Bill down $$$ more than half !!!

So if i had this AC Unit setup to use Centigrade degrees ... would it control temps to + or - 1.0 degrees ??
1.0 degC = 1.8 DegF

example i set the AC at 24.0 DegC = 75.2 DegF
if the Digital Thermostat maintains 24.0 DegC to within + or - 1.0 DegC then its equal to 73.4 DegF to 77.0 DegF = 3.6 deg F range ... back to room temp hassle

Those with Digital Thermostat reading in Centigrade degrees
what do you set your Thermostat to if you wanted just a 1.0 DegF change ???
could you enter in a DegC temp like 24.44444 to get 76.0 DegF room temperature

are your Digital Thermostat's readings in 1.0 degC increments ? or can you input 1/2 degC ??