PureBasic Forums - English

Posted: **Mon Oct 31, 2016 5:47 pm**

Hello!

t$="0.60"
Debug ValF(t$)

Instead of 0.60 it says 0.60000002384186.

How do I get 0.60?

Thanks!

Posted: **Mon Oct 31, 2016 6:14 pm**

Code: Select all

t$="0.60"
Debug StrF(ValF(t$), 2)

Posted: **Mon Oct 31, 2016 6:17 pm**

marcoagpinto wrote:How do I get 0.60?!

Code: Select all

t$ = "0.60"
t.f = ValF(t$)
Debug StrF(t, 2)

Posted: **Mon Oct 31, 2016 7:35 pm**

It doesn't convert exactly because some decimal numbers can't be represented in binary exactly eg 0.1 expands to 0.000110011001100110011 recurring..

http://www.exploringbinary.com/why-0-po ... ing-point/

I presume as 0.6 is 0.1 * 6 it is why you get the 0.60000002384186. it is the closest that can be done in binary.

It has big implications for financial software and you should always represent money as integers of the smallest division ie pence, cent etc and then just divide by 100 to represent the pound/euro/dollar.

Michael

Posted: **Tue Nov 01, 2016 12:13 am**

Also, you can use Double instead of Float (unless using an API function that requires float)

Posted: **Tue Nov 01, 2016 9:47 am**

tastyraspberry wrote:
It has big implications for financial software and you should always represent money as integers of the smallest division ie pence, cent etc and then just divide by 100 to represent the pound/euro/dollar.

Michael

This is true, but I've had trouble in the past displaying the result becasue you have to convert back to a string to do so ( using StrF or StrD ) and would love for PB to have currency handling functions built in.

Posted: **Wed Nov 02, 2016 2:00 am**

captain_skank wrote:
tastyraspberry wrote:
It has big implications for financial software and you should always represent money as integers of the smallest division ie pence, cent etc and then just divide by 100 to represent the pound/euro/dollar.

Michael
This is true, but I've had trouble in the past displaying the result becasue you have to convert back to a string to do so ( using StrF or StrD ) and would love for PB to have currency handling functions built in.

for decimal currencies (ie Pounds, Euros, Dollars), perhaps something like this to displaying the integer?

Code: Select all

currency.l = 12345 ; $123.45
output$ = Str(currency/100) + "." + Str(currency%100)
debug output$

Posted: **Wed Nov 02, 2016 2:28 am**

Thanks, guys!

Posted: **Wed Nov 02, 2016 9:08 am**

@citystate,

May I suggest the slight modification to take care of less than 10 cents.

Code: Select all

currency.l = 12305 ; $123.05
output$ = Str(currency/100) + "." + RSet(Str(currency%100),2,"0")
Debug output$[/quote]

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