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bit swap from c to PB
Posted: Wed Oct 12, 2016 3:04 pm
by supercdfr
i have this in c :
Code: Select all
printf("%u\n\n\n",(3967115105 << 28) | (3967115105 >> 4) )
And i have the result : 516380150 that is correct
When i try whit PB, i have this :
Code: Select all
Debug (3967115105 << 28) | (3967115105 >> 4)
i have 1064914352463107574 that is incorrect.
I try stru, strd strf, but the result is always false.
Re: bit swap from c to PB
Posted: Wed Oct 12, 2016 3:25 pm
by Shardik
To obtain a long integer you have to remove all unwanted digits with an AND $FFFFFFFF operation. The following code line therefore displays your wanted result:
Code: Select all
Debug ((3967115105 << 28) | (3967115105 >> 4)) & $FFFFFFFF ; Displays 516380150
Re: bit swap from c to PB
Posted: Wed Oct 12, 2016 3:48 pm
by supercdfr
1000 thanks
Re: bit swap from c to PB
Posted: Wed Oct 12, 2016 4:37 pm
by skywalk
Code: Select all
EnableExplicit
Define.q q = (3967115105 << 28) | (3967115105 >> 4)
Define.l l = q
Debug q
Debug l
l = ((3967115105 << 28) | (3967115105 >> 4)) ;OVERFLOW; & $FFFFFFFF
;[11:35:02] [COMPILER] Line 5: Overflow error: a 'long' value (.l) must be between -2147483648 And +4294967295.
Re: bit swap from c to PB
Posted: Wed Oct 12, 2016 5:14 pm
by wilbert
Code: Select all
l.l = 3967115105
EnableASM
ror l, 4
DisableASM
Debug l