About RegularExpression replace \1
Posted: Sat Sep 17, 2011 9:12 am
a.s="fsvFfs123fkasdjfk467566"
CreateRegularExpression(0,"(Ffs)(\d)")
ReplaceRegularExpression(0,a.s,"\1")
i want the result is
Ffs123
cann't suport \1\2 ？
example
i want debug output
abC
CreateRegularExpression(0,"(Ffs)(\d)")
ReplaceRegularExpression(0,a.s,"\1")
i want the result is
Ffs123
cann't suport \1\2 ？
example
Code: Select all
If CreateRegularExpression(0, "(abC)(.+)")
Result$ = ReplaceRegularExpression(0, "abC ABc zbA abc", "\1")
Debug Result$ ; Will print "--- ABc --- abc"
Else
Debug RegularExpressionError()
EndIf
abC