@localmotion34, No offence, but I think hanzProf is nearer the truth than you are. It doesn't make
sense to crack ExeCryptor, then keep this fact a secret.
If I understand ExeCryptor's workings right, I can decide which part of the code is to be obfuscated
(at the machine code level), and to what degree. The protected code can for example be a 100 times
bigger than normal, and must be manually back-tracked first to understand what the code do.
This is virtually impossible
The below is obfuscated source code, what if it were 100 pages of pure machine code? The best thing
is, next time a program is compiled int a new minor version, the code looks completely different again
and the crackers have to do it all over again
Code: Select all
#define O(b,f,u,s,c,a)b(){int o=f();switch(*p++){X u:_ o s b();X c:_ o a b();
default:p--;_ o;}}
#define t(e,d,_,C)X e:f=fopen(B+d,_);C;fclose(f)
#define U(y,z)while(p=Q(s,y))*p++=z,*p=' '
#define N for(i=0;i<11*R;i++)m[i]&&
#define I "%d %s\n",i,m[i]
#define X ;break;case
#define _ return
#define R 999
typedef char*A;int*C,E[R],L[R],M[R],P[R],l,i,j;char B[R],F[2];A m[12*R],malloc
(),p,q,x,y,z,s,d,f,fopen();A Q(s,o)A s,o;{for(x=s;*x;x++){for(y=x,z=o;*z&&*y==
*z;y++)z++;if(z>o&&!*z)_ x;}_ 0;}main(){m[11*R]="E";while(puts("Ok"),gets(B)
)switch(*B){X'R':C=E;l=1;for(i=0;i<R;P[i++]=0);while(l){while(!(s=m[l]))l++;if
(!Q(s,"\"")){U("<>",'#');U("<=",'$');U(">=",'!');}d=B;while(*F=*s){*s=='"'&&j
++;if(j&1||!Q(" \t",F))*d++=*s;s++;}*d--=j=0;if(B[1]!='=')switch(*B){X'E':l=-1
X'R':B[2]!='M'&&(l=*--C)X'I':B[1]=='N'?gets(p=B),P[*d]=S():(*(q=Q(B,"TH"))=0,p
=B+2,S()&&(p=q+4,l=S()-1))X'P':B[5]=='"'?*d=0,puts(B+6):(p=B+5,printf("%d\n",S
()))X'G':p=B+4,B[2]=='S'&&(*C++=l,p++),l=S()-1 X'F':*(q=Q(B,"TO"))=0;p=B+5;P[i
=B[3]]=S();p=q+2;M[i]=S();L[i]=l X'N':++P[*d]<=M[*d]&&(l=L[*d]);}else p=B+2,P[
*B]=S();l++;}X'L':N printf(I)X'N':N free(m[i]),m[i]=0 X'B':_ 0 t('S',5,"w",N
fprintf(f,I))t('O',4,"r",while(fgets(B,R,f))(*Q(B,"\n")=0,G()))X 0:default:G()
;}_ 0;}G(){l=atoi(B);m[l]&&free(m[l]);(p=Q(B," "))?strcpy(m[l]=malloc(strlen(p
)),p+1):(m[l]=0,0);}O(S,J,'=',==,'#',!=)O(J,K,'<',<,'>',>)O(K,V,'$',<=,'!',>=)
O(V,W,'+',+,'-',-)O(W,Y,'*',*,'/',/)Y(){int o;_*p=='-'?p++,-Y():*p>='0'&&*p<=
'9'?strtol(p,&p,0):*p=='('?p++,o=S(),p++,o:P[*p++];}