PureBasic Forums - English

idle wrote: Mon Jul 17, 2023 11:23 pm √(-shit²) Shit just got real

Erm...no. The root of a negative, real number is an imaginary number: https://en.wikipedia.org/wiki/Imaginary ... prov=sfla1

It's (-shit)² and not -(shit²)

PS: you can replace Red() by Int() or Bool() or whatever

Lord wrote: Tue Jul 18, 2023 9:12 am It's (-shit)² and not -(shit²)

Ah sh..., you're right. Or not? https://www.wolframalpha.com/input?i2d= ... 5C%2841%29
How about √(|shit|) ?

6/2(1+2) = 9
or
6/2(1+2) = 1
?
The answer depends on your calculator...

From left to right :
6/2(1+2) = 3(1+2) = 3×3 = 9
6/[2(1+2)] = 6/[2×3] = 6/6 = 1

Olli wrote: Mon Jul 17, 2023 11:03 pm

Heh... isn't that really great? I read a wonderful explanation of how he got the equation (deducting from sin/cos formulas) but cannot remember the book

fsw wrote: Wed Jul 19, 2023 5:58 am 6/2(1+2) = 9
or
6/2(1+2) = 1
?
The answer depends on your calculator...

Maybe I'm missing something, but if calculator respects parenthesis, isn't it always 9?

Piero wrote: Sun Jul 30, 2023 6:26 am

Olli wrote: Mon Jul 17, 2023 11:03 pm

Heh... isn't that really great? I read a wonderful explanation of how he got the equation (deducting from sin/cos formulas) but cannot remember the book

+

Piero wrote: Sun Jul 30, 2023 6:32 am

fsw wrote: Wed Jul 19, 2023 5:58 am 6/2(1+2) = 9
or
6/2(1+2) = 1
?
The answer depends on your calculator...

Maybe I'm missing something, but if calculator respects parenthesis, isn't it always 9?

=



for piero : on 4th minute and 17th second, when the guy starts to shoot the e exponential symbol, cos and sin appear !!
Else you have this :
e^(ix) = cos(x) + iSin(x)

and if you want to see a simple man who walks, here is a link..

Olli wrote: Sun Jul 30, 2023 1:45 pm

6/2(1+2) = 6*1/2*3

Note :

i is considered as a vector.

i is defined as i * i = (-1)

As (-1) * (-1) = 1,
i * i * i * i = 1

And i * i * i * i is also considered as a vector
This vector is as i / i.

If we represent the two vectors i and i / i on a right plane, we can consider that, if i^(4*k) = 1 (k being a relative integer number), then there are 4 directions for the vectors i^(4*k). i is constant. So the 4 angles between the 4 directions are the same ones. So, the vectors i^1 and i^0 are perpendicular on this right plane.

By extension, if we consider :
i * i = -1
j * j = -1
k * k = -1
In a space, where we forget i^0 as a vector, there is a mechanic to find several relative directions for i, j and k in this space (as i * i * i * i = 1) from this : i * k * j / 1 = 1.

Olli wrote: Wed Aug 02, 2023 3:58 am from this : i * k * j / 1 = 1.

Nice tribute! Note that the notion of using three distinct imaginary numbers i, j and k to apply 3 directions in a space, had its first hours in Hamilton's mind.

What it is off topic, but it surprises me a lot, is the death we give to this brilliant mind :
<< He [Hamilton] died on 2 September 1865, following a severe attack of gout. >>

I am very surprised, because Jacques Psychriste discovered that colchicum was an antidote for gout attacks, 1300 years earlier !

Plus colchicum appears naturally in Europa every year on September, since the greek gold age !

I am subject to this disease, and never I will die by this disease, even if it would be 100 times more strong on me. Colchicum acts two hours after a taken, and we must calculate precisely and beforehand according to its weight (else it's a very powerful poison).

Hamilton was however a mathematician...