Low word without peek?

[Justin]

Is there any way(i guess using shift operators) to get the low word of a long without using peekw(@long) ? , i do this to reduce exe size.

i did this asm proc but i think can be done using operators ¿?

Code: Select all

procedure peekw_(hbuf)
r.w
mov edi,hbuf 
mov ax,word [edi]
mov r,ax
procedurereturn r
endprocedure

[freak]

Code: Select all

LoWord = Long & $FFFF
HiWord = Long >> 16

Timo

[traumatic]

loWord = var.l & $FFFF
hiWord = var.l >> 16

[traumatic]

ahhhh, too late... damn dial-up!

[Justin]

Ok thanks, much easier. Do you know if it's faster or slower?, i'll use to process the WM_COMMAND msg inside the window callback.

[tinman]

Ok thanks, much easier. Do you know if it's faster or slower?, i'll use to process the WM_COMMAND msg inside the window callback.

Don't know about quicker, but I guess using the & and >> operators would be preferrable as your peek method relies on little endian byte ordering (i.e. would not work on 68k, probably not on PPC depending on what mode it was in). I guess it only matters if you care about portability and hope that there is one day a PPC/Linux or Mac version of PB ;)

I think Fred once said that simple commands like Peek, Sin, etc were all made inline by the compiler, but I could be wrong.

[El_Choni]

Freak's code is much faster than calling that peekw procedure, no doubt.