Get Windows XP CD Key

PB · Post by PB » Sun Dec 05, 2004 11:57 am

Can someone please convert this Visual Basic code to PureBasic? I had a
go without any success (I'm crap at maths and using Xor/Mod etc).

Code: Select all


'**************************************
' Name: View Windows XP CD Key
' Description:Function: sGetXPCDKey() wi
'     ll return the CD Key for Windows XP in t
'     he format XXXXX-XXXXX-XXXXX-XXXXX-XXXXX.
'     
' By: Snytax
'
' Inputs:Nothing.
'
' Returns:Your Windows XP CD Key.
'
'This code is copyrighted and has' limited warranties.Please see http://w
'     ww.Planet-Source-Code.com/vb/scripts/Sho
'     wCode.asp?txtCodeId=57164&lngWId=1'for details.'**************************************

'sGetXPCDKey() -
'Returns the Windows XP CD Key if succes
'     sful.
'Returns nothing upon failure.

Public Function sGetXPCDKey() As String

    'Read the value of:
    'HKLM\SOFTWARE\MICROSOFT\Windows NT\Curr
    '     entVersion\DigitalProductId
    Dim bDigitalProductID() As Byte
    Dim bProductKey() As Byte
    Dim ilByte As Long
    Dim lDataLen As Long
    Dim hKey As Long
    'Open the registry key: HKLM\SOFTWARE\MI
    '     CROSOFT\Windows NT\CurrentVersion

    If RegOpenKey(HKEY_LOCAL_MACHINE, "SOFTWARE\MICROSOFT\Windows NT\CurrentVersion", hKey) = ERROR_SUCCESS Then
        lDataLen = 164
        ReDim Preserve bDigitalProductID(lDataLen)
        'Read the value of DigitalProductID

        If RegQueryValueEx(hKey, "DigitalProductId", 0&, REG_BINARY, bDigitalProductID(0), lDataLen) = ERROR_SUCCESS Then
            'Get the Product Key, 15 bytes long, off
            '     set by 52 bytes
            ReDim Preserve bProductKey(14)


            For ilByte = 52 To 66
                bProductKey(ilByte - 52) = bDigitalProductID(ilByte)
            Next ilByte

        Else
            'ERROR: Could not read "DigitalProductID
            '     "
            sGetXPCDKey = ""
            Exit Function
        End If

    Else
        'ERROR: Could not open "HKLM\SOFTWARE\MI
        '     CROSOFT\Windows NT\CurrentVersion"
        sGetXPCDKey = ""
        Exit Function
    End If

    'Now we are going to 'base24' decode the
    '     Product Key
    Dim bKeyChars(0 To 24) As Byte
    'Possible characters in the CD Key:
    bKeyChars(0) = Asc("B")
    bKeyChars(1) = Asc("C")
    bKeyChars(2) = Asc("D")
    bKeyChars(3) = Asc("F")
    bKeyChars(4) = Asc("G")
    bKeyChars(5) = Asc("H")
    bKeyChars(6) = Asc("J")
    bKeyChars(7) = Asc("K")
    bKeyChars(8) = Asc("M")
    bKeyChars(9) = Asc("P")
    bKeyChars(10) = Asc("Q")
    bKeyChars(11) = Asc("R")
    bKeyChars(12) = Asc("T")
    bKeyChars(13) = Asc("V")

    bKeyChars(14) = Asc("W")
    bKeyChars(15) = Asc("X")
    bKeyChars(16) = Asc("Y")
    bKeyChars(17) = Asc("2")
    bKeyChars(18) = Asc("3")
    bKeyChars(19) = Asc("4")
    bKeyChars(20) = Asc("6")
    bKeyChars(21) = Asc("7")
    bKeyChars(22) = Asc("8")
    bKeyChars(23) = Asc("9")
    Dim nCur As Integer
    Dim sCDKey As String
    Dim ilKeyByte As Long
    Dim ilBit As Long

    For ilByte = 24 To 0 Step -1
        'Step through each character in the CD k
        '     ey
        nCur = 0


        For ilKeyByte = 14 To 0 Step -1
            'Step through each byte in the Product K
            '     ey
            nCur = nCur * 256 Xor bProductKey(ilKeyByte)
            bProductKey(ilKeyByte) = Int(nCur / 24)
            nCur = nCur Mod 24
        Next ilKeyByte

        sCDKey = Chr(bKeyChars(nCur)) & sCDKey
        If ilByte Mod 5 = 0 And ilByte <> 0 Then sCDKey = "-" & sCDKey
    Next ilByte

    sGetXPCDKey = sCDKey
End Function

blueznl · Post by **blueznl** » Sun Dec 05, 2004 12:48 pm

you could just peek at the sleeve of your original disk...

HeX0R · Post by **HeX0R** » Sun Dec 05, 2004 4:24 pm

Did i ever mention, that i really hate the signed byte-variables in pb ?

But anyway, here we go :

Code: Select all

;**************************************
; Name: View Windows XP CD Key
; Description:Function: sGetXPCDKey() wi
;     ll Return the CD Key For Windows XP in t
;     he format XXXXX-XXXXX-XXXXX-XXXXX-XXXXX.
;     
; By: Snytax
;
; Inputs:Nothing.
;
; Returns:Your Windows XP CD Key.
;
;This code is copyrighted And has' limited warranties.Please see http://w
;     ww.Planet-Source-Code.com/vb/scripts/Sho
;     wCode.asp?txtCodeId=57164&lngWId=1'For details.'**************************************
;
;sGetXPCDKey() -
;Returns the Windows XP CD Key If succes
;     sful.
;Returns nothing upon failure.

Procedure.s sGetXPCDKey()

    ;Read the value of:
    ;HKLM\SOFTWARE\MICROSOFT\Windows NT\Curr
    ;     entVersion\DigitalProductId
    *bDigitalProductID = AllocateMemory(164)
    *bProductKey.b = AllocateMemory(15)
    ilByte.l
    lDataLen.l
    hKey.l
    ;Open the registry key: HKLM\SOFTWARE\MI
    ;     CROSOFT\Windows NT\CurrentVersion
    If RegOpenKey_(#HKEY_LOCAL_MACHINE, "SOFTWARE\MICROSOFT\Windows NT\CurrentVersion", @hKey) = #ERROR_SUCCESS
        lDataLen = 164
        ;ReDim Preserve bDigitalProductID(lDataLen)
        ;Read the value of DigitalProductID

        If RegQueryValueEx_(hKey, "DigitalProductId", 0, "REG_BINARY", *bDigitalProductID, @lDataLen) = #ERROR_SUCCESS
            ;Get the Product Key, 15 bytes long, off
            ;     set by 52 bytes

            For ilByte = 52 To 66
                Byte.l = PeekB(*bDigitalProductID + ilByte) & 255
                PokeB(*bProductKey + ilByte - 52, Byte)
            Next ilByte
            RegCloseKey_(hKey)
        Else
            ;ERROR: Could not Read "DigitalProductID
            RegCloseKey_(hKey)
            ProcedureReturn ""
        EndIf
    Else
        ;ERROR: Could not open "HKLM\SOFTWARE\MI
        ;     CROSOFT\Windows NT\CurrentVersion"
        ProcedureReturn ""
    EndIf
    ;Now we are going To 'base24' decode the
    ;     Product Key
    Dim bKeyChars.l(23)
    ;Possible characters in the CD Key:
    bKeyChars(0) = Asc("B")
    bKeyChars(1) = Asc("C")
    bKeyChars(2) = Asc("D")
    bKeyChars(3) = Asc("F")
    bKeyChars(4) = Asc("G")
    bKeyChars(5) = Asc("H")
    bKeyChars(6) = Asc("J")
    bKeyChars(7) = Asc("K")
    bKeyChars(8) = Asc("M")
    bKeyChars(9) = Asc("P")
    bKeyChars(10) = Asc("Q")
    bKeyChars(11) = Asc("R")
    bKeyChars(12) = Asc("T")
    bKeyChars(13) = Asc("V")

    bKeyChars(14) = Asc("W")
    bKeyChars(15) = Asc("X")
    bKeyChars(16) = Asc("Y")
    bKeyChars(17) = Asc("2")
    bKeyChars(18) = Asc("3")
    bKeyChars(19) = Asc("4")
    bKeyChars(20) = Asc("6")
    bKeyChars(21) = Asc("7")
    bKeyChars(22) = Asc("8")
    bKeyChars(23) = Asc("9")
    nCur.l
    sCDKey.s
    ilKeyByte.l
    ilByte.l
    byte.l
    For ilByte = 24 To 0 Step -1
        ;Step through each character in the CD k
        ;     ey
        nCur = 0
        For ilKeyByte = 14 To 0 Step -1
            ;Step through each byte in the Product K
            ;     ey
            byte = PeekB(*bProductKey + ilKeyByte) & 255
            nCur = ((nCur & 255) * 256) ! byte
            PokeB(*bProductKey + ilKeyByte, (Int(nCur / 24)))
            nCur = nCur % 24
        Next ilKeyByte
        sCDKey = Chr(bKeyChars(nCur)) + sCDKey
        If ilByte % 5 = 0 And ilByte <> 0
          sCDKey = "-" + sCDKey
        EndIf
    Next ilByte
    ProcedureReturn sCDKey

EndProcedure


Debug sGetXPCDKey()
End

PolyVector · Post by **PolyVector** » Sun Dec 05, 2004 5:09 pm

damn HeX0R, you beat me

PB · Post by PB » Sun Dec 05, 2004 9:08 pm

Thanks, HeX0R!

It's always fun to beat Microsoft's encryption.

gnozal · Post by **gnozal** » Mon Dec 06, 2004 2:59 pm

Thanks.
But are you sure about this *bProductKey.b = AllocateMemory(15)
Should'nt it be a long ?

traumatic · Post by **traumatic** » Mon Dec 06, 2004 3:34 pm

gnozal wrote:Thanks.
But are you sure about this *bProductKey.b = AllocateMemory(15)
Should'nt it be a long ?

Why?

1)

Code: Select all

Dim bProductKey() As Byte

2) If it were a long, the name was "iProductKey" for sure

gnozal · Post by **gnozal** » Mon Dec 06, 2004 3:45 pm

traumatic wrote:Why?

Because the pointer returned by AllocateMemory() is 32 bit long, and a byte is 8 bit long ?

traumatic · Post by **traumatic** » Mon Dec 06, 2004 3:57 pm

gnozal wrote:
traumatic wrote:Why?
Because the pointer returned by AllocateMemory() is 32 bit long, and a byte is 8 bit long ?

Ah, I thought you meant the original VB source. Sorry.

PolyVector · Post by **PolyVector** » Mon Dec 06, 2004 4:18 pm

In that example isn't *bProductKey.b a 32bit Long pointer to a Byte?

Code: Select all

*bProductKey.b
Debug SizeOf(*bProductKey)

Although, in PB there's no real way to access the byte without using a structure...hehe

fsw · Post by **fsw** » Fri Apr 13, 2007 9:53 pm

Does this work on Vista?

SFSxOI · Post by **SFSxOI** » Fri Apr 13, 2007 9:55 pm

fsw wrote:Does this work on Vista?

yes

Tranquil · Post by **Tranquil** » Sat Apr 14, 2007 9:30 am

You can even take a look on your Computer-Administration (dont know how this is called on an english installation of Windows Vista). The CD Key is also shown here.